4x^2=80(3x)

Solution for 4x^2=80(3x) equation:

4x^2=80(3x)

We move all terms to the left:

4x^2-(80(3x))=0

determiningTheFunctionDomain
4x^2-803x=0

a = 4; b = -803; c = 0;
Δ = b2-4ac
Δ = -8032-4·4·0
Δ = 644809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{644809}=803$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-803)-803}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-803)+803}{2*4}=\frac{1606}{8}
=200+3/4
$